(c^2-6)=(2c^2+3c-1)

Solution for (c^2-6)=(2c^2+3c-1) equation:

(c^2-6)=(2c^2+3c-1)

We move all terms to the left:

(c^2-6)-((2c^2+3c-1))=0

We get rid of parentheses

c^2-((2c^2+3c-1))-6=0


We calculate terms in parentheses: -((2c^2+3c-1)), so:

(2c^2+3c-1)

We get rid of parentheses

2c^2+3c-1

Back to the equation:

-(2c^2+3c-1)


We get rid of parentheses

c^2-2c^2-3c+1-6=0

We add all the numbers together, and all the variables

-1c^2-3c-5=0

a = -1; b = -3; c = -5;
Δ = b2-4ac
Δ = -32-4·(-1)·(-5)
Δ = -11
Delta is less than zero, so there is no solution for the equation